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KVA to KW Converter - Understanding Apparent and Real Power

Learn how to convert apparent power in kilovolt-amps (kVA) to real power in kilowatts (kW) using power factor. Complete guide with formulas, examples, and applications.

Enginist Engineering Team
Professional electrical engineers with expertise in power systems, circuit design, and electrical code compliance.
Reviewed by PE-Licensed Electrical Engineers
Published: October 19, 2025
Updated: November 9, 2025

KVA to KW Converter - Understanding Apparent and Real Power

Quick AnswerHow do you convert kVA to kW?
Convert kVA to kW by multiplying by power factor. Typical PF values: motors 0.75-0.90, LED loads 0.9-0.95, resistive loads 1.0. kVA determines equipment sizing; kW determines actual usable power.
kW=kVA×PFkW = kVA \times PF
Example

100 kVA transformer at PF=0.85 delivers kW = 100 × 0.85 = 85 kW real power

Introduction

When evaluating equipment capacity, a 100 kVA transformer or generator doesn't deliver 100 kW of usable power—power factor determines how much real power you actually get. Understanding this kVA-to-kW relationship is essential for matching equipment to load requirements.

Why This Conversion Matters

Transformers, generators, and UPS systems are rated in kVA because they must supply total current regardless of whether that current does useful work. But your loads consume kW—the real power that drives motors, lights buildings, and runs equipment. A 100 kVA generator with loads at 0.85 power factor delivers only 85 kW, not 100 kW. If your load requires 95 kW, that "100 kVA" unit is undersized. This conversion prevents equipment oversizing (wasting capital) or undersizing (causing failures).

The Fundamental Challenge

The gap between kVA and kW comes from reactive power—the energy that oscillates between source and load in systems with motors, transformers, and electronic equipment. Power factor quantifies this gap but varies significantly: a motor at full load might have 0.88 power factor, but the same motor at quarter load drops to 0.65. This guide shows how to account for these variations when selecting and loading electrical equipment.

What You'll Learn

This guide covers the kVA-to-kW conversion with power factor considerations per IEC 60050-131 definitions. You'll understand why equipment kVA ratings differ from kW delivery, how to verify generator and transformer capacity for specific loads, and when power factor correction makes economic sense. Reference tables provide typical power factors for common equipment types and operating conditions.

Quick Answer: How to Convert kVA to kW

Convert apparent power (kVA) to real power (kW) by multiplying by the power factor.

Core Formula

P (kW)=S (kVA)×PFP\ (\text{kW}) = S\ (\text{kVA}) \times PF

Where:

  • PP = Real electrical power (kW)
  • SS = Apparent wattage (kVA)
  • PFPF = Load factor (0 to 1.0)

Additional Formulas

FormulaFormula ExpressionPurpose
Capacity FactorPF=P(kW)S(kVA)PF = \frac{P(\text{kW})}{S(\text{kVA})}Calculate energy factor from real and apparent electrical power
Reactive WattageQ (kVAr)=S2P2Q\ (\text{kVAr}) = \sqrt{S^2 - P^2}Calculate reactive component using load triangle

Worked Example

Convert 100 kVA to kW with PF=0.85

Given:

  • Apparent capacity: S=100S = 100 kVA
  • Energy factor: PF=0.85PF = 0.85

Calculation:

P=100×0.85=85 kWP = 100 \times 0.85 = \mathbf{85\ \text{kW}}

Result: 100 kVA = 85 kW at 0.85 power factor

Reference Table

ParameterTypical RangeStandard
Power Factor (Unity)1.0Resistive loads only
Power Factor (Good)0.90-0.95Well-designed systems
Power Factor (Fair)0.85-0.90Acceptable, correction recommended
Power Factor (Poor)< 0.85Correction required
Utility Requirement> 0.90Most utilities

Key Standards

In AC electrical systems, there are three types of energy:

  • Real Electrical power (kW): The actual wattage consumed by resistive loads, measured in kilowatts
  • Reactive Load (kVAR): The capacity used to create magnetic fields, measured in kilovolt-amperes reactive
  • Apparent Energy (kVA): The vector sum of real and reactive electrical power, measured in kilovolt-amperes

The relationship between these powers is described by the wattage triangle and load factor.

Understanding Power Types

Real Power (kW)

Real capacity is the actual energy that does useful work in an electrical system. It's consumed by resistive loads like heaters, incandescent lights, and motors under load.

Characteristics:

  • Measured in kilowatts (kW)
  • Represents actual energy consumption
  • Causes electricity meter to register
  • Generates heat in resistive elements

Reactive Power (kVAR)

Reactive electrical power is the wattage required to create and maintain magnetic fields in inductive loads like motors, transformers, and fluorescent lights.

Characteristics:

  • Measured in kilovolt-amperes reactive (kVAR)
  • Does not perform useful work
  • Causes current to lag or lead voltage
  • Increases system losses
  • Does not register on electricity meters (in many cases)

Apparent Power (kVA)

Apparent load is the vector sum of real and reactive capacity. It represents the total energy that must be supplied by the source.

Characteristics:

  • Measured in kilovolt-amperes (kVA)
  • Determines equipment sizing
  • Includes both real and reactive components
  • Used for transformer and generator ratings

Power Factor (PF)

Electrical reactive power ratio is the ratio of real wattage to apparent load, representing the performance of capacity usage.

PF=P(kW)S(kVA)PF = \frac{P(\text{kW})}{S(\text{kVA})}

Energy Factor Values:

  • 1.0 (Unity): Pure resistive load, ideal case
  • 0.9-0.95: Good electrical power factor, typical for well-designed systems
  • 0.8-0.9: Acceptable wattage factor
  • < 0.8: Poor load factor, correction recommended

The Formula

Basic Formula

The formula to convert apparent capacity to real energy is:

P(kW)=S(kVA)×PFP(\text{kW}) = S(\text{kVA}) \times PF

Where:

  • P(kW) = Real electrical power in kilowatts
  • S(kVA) = Apparent wattage in kilovolt-amperes
  • PFPF = Load factor (0 to 1)

Formula Explanation

The formula works by:

  1. Taking the apparent capacity in kVA
  2. Multiplying by the energy factor to get real electrical power
  3. The result is the actual wattage consumed

Power Triangle

The relationship between real, reactive, and apparent load can be visualized using the capacity triangle:

S (kVA) /| / | / | Q (kVAR) / | / | /_____| P (kW)

Where: S2=P2+Q2S^2 = P^2 + Q^2

Step-by-Step Calculation

Example 1: Simple Conversion

Problem: A transformer has a rating of 100 kVA with a electrical cosϕ\phi value of 0.85. What is the real wattage?

Solution:

  1. Identify the given values:

    • Apparent Load (S) = 100 kVA
    • Capacity Factor (PF) = 0.85
  2. Apply the formula: P (kW)=S (kVA)×PFP\ (\text{kW}) = S\ (\text{kVA}) \times PF P (kW)=100×0.85=85 kWP\ (\text{kW}) = 100 \times 0.85 = 85 \text{ kW}

  3. Interpret the result: The real energy is 85 kW, meaning the transformer can supply 85 kW of actual electrical power.

Example 2: Low Power Factor

Problem: A motor draws 50 kVA with a wattage factor of 0.7. Find the real load.

Solution:

  1. Given values:

    • Apparent Capacity (S) = 50 kVA
    • Energy Factor (PF) = 0.7
  2. Analysis: P (kW)=50×0.7=35 kWP\ (\text{kW}) = 50 \times 0.7 = 35 \text{ kW}

  3. Result: The machine consumes 35 kW of real electrical power despite drawing 50 kVA.

Practical Examples

Example 3: Industrial Load

Scenario: An industrial facility has a 500 kVA transformer operating at 0.82 wattage factor. Evaluate the real load capacity.

Given:

  • Apparent Capacity = 500 kVA
  • Energy Factor = 0.82

Determination: P (kW)=500×0.82=410 kWP\ (\text{kW}) = 500 \times 0.82 = 410 \text{ kW}

Result: The transformer can supply 410 kW of real electrical power.

Example 4: Motor Efficiency

Scenario: A 75 kVA drive unit operates at 0.88 wattage factor. What is the real load output?

Given:

  • Apparent Capacity = 75 kVA
  • Energy Factor = 0.88

Evaluation: P (kW)=75×0.88=66 kWP\ (\text{kW}) = 75 \times 0.88 = 66 \text{ kW}

Result: The electrical power unit consumes 66 kW of real wattage.

Example 5: phase angle Improvement

Scenario: After load factor correction, a arrangement's capacity factor improved from 0.75 to 0.95. The apparent energy is 200 kVA. Measure the real electrical power before and after correction.

Before Correction: P (kW)=200×0.75=150 kWP\ (\text{kW}) = 200 \times 0.75 = 150 \text{ kW}

After Correction: P (kW)=200×0.95=190 kWP\ (\text{kW}) = 200 \times 0.95 = 190 \text{ kW}

Result: The real wattage increased from 150 kW to 190 kW with the same apparent load.

Power Factor Correction

Why power coefficient Matters

Low capacity factor causes:

  • Higher current for the same real energy
  • Increased line losses
  • Reduced mechanism capacity
  • Higher electricity costs (in some tariffs)
  • Voltage drops

Benefits of Power Factor Correction

Improving electrical reactive power ratio provides:

  • Reduced apparent wattage requirements
  • Lower line losses
  • Increased installation capacity
  • Better potential regulation
  • Potential cost savings

Methods of Correction

  1. Capacitor Banks: Add capacitance to offset inductive loads
  2. Synchronous Condensers: Rotating machines that provide reactive load
  3. Active Capacity Factor Correction: Electronic circuits for small loads
  4. Load Management: Optimize load distribution

Typical Power Factors

Load TypeTypical Energy Factor
Incandescent Lights1.0
Resistance Heaters1.0
Motors (Full Load)0.85-0.90
Motors (Half Load)0.70-0.80
Fluorescent Lights0.50-0.90
Induction Furnaces0.60-0.70
Arc Welding0.35-0.60

Standards and References

International Standards

  • IEC 60050-131: International Electrotechnical Vocabulary - Electricity and magnetism
  • IEC 61000-2-2: Electromagnetic compatibility - Environment
  • IEEE 519: Recommended practices for harmonic control

Key Definitions

Real Electrical power (kW): The actual wattage consumed by resistive loads, measured in kilowatts.

Reactive Load (kVAR): The capacity required to create magnetic fields in inductive loads.

Apparent Energy (kVA): The vector sum of real and reactive electrical power, measured in kilovolt-amperes.

Wattage Factor: The ratio of real load to apparent capacity, representing energy usage effectiveness.

Our calculations follow industry best practices and have been validated against real-world scenarios.

Conclusion

Converting apparent power (kVA) to real power (kW) using power factor is essential for electrical system design, equipment sizing and selection, power factor correction planning, cost optimization, and system efficiency improvement. Understanding the relationship between kVA, kW, and power factor enables engineers to design efficient electrical systems, optimize power usage, and reduce operational costs. The conversion formula P(kW) = S(kVA) × PF is fundamental to determining the actual useful power that can be delivered from equipment rated in apparent power.

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Key Takeaways

  • Convert kVA to kW using the formula: P(kW) = S(kVA) × PF, where PF is power factor ranging from 0 to 1.0
  • kVA is always greater than or equal to kW because apparent power includes both real power (kW) and reactive power (kVAR) components
  • Typical power factors: unity (1.0) for resistive loads, 0.90-0.95 for well-designed systems, 0.85-0.90 for acceptable systems, below 0.85 requires correction
  • Equipment rated in kVA (transformers, generators) must be converted to kW using power factor to determine actual useful power capacity
  • Most utilities require power factor > 0.90 to avoid penalties; power factor correction can reduce kVA requirements and improve system efficiency
  • Always use measured or nameplate power factor values when available, as typical values may not reflect actual system conditions

Further Learning

References & Standards

This guide follows established engineering principles and standards. For detailed requirements, always consult the current adopted edition in your jurisdiction.

Primary Standards

IEC 60050-131 International Electrotechnical Vocabulary - Part 131: Electric and magnetic circuits. Defines kVA as apparent power and kW as real power.

IEC 61000-4-30 Electromagnetic compatibility (EMC) - Part 4-30: Testing and measurement techniques - Power quality measurement methods. Provides standards for power factor measurement.

Supporting Standards & Guidelines

National Electrical Code (NEC) Comprehensive electrical safety standards for the United States.

IEEE Std 519 Recommended Practice and Requirements for Harmonic Control in Electric Power Systems. Provides guidance on power factor correction for systems with harmonics.

IEC 60050 - International Electrotechnical Vocabulary International standards for electrical terminology and definitions.

NEMA Publications National Electrical Manufacturers Association standards for electrical equipment.

Further Reading

Note: Standards and codes are regularly updated. Always verify you're using the current adopted edition applicable to your project's location. Consult with local authorities having jurisdiction (AHJ) for specific requirements.


Disclaimer: This guide provides general technical information based on international electrical standards. Always verify calculations with applicable local electrical codes (NEC, IEC, BS 7671, etc.) and consult licensed electrical engineers or electricians for actual installations. Electrical work should only be performed by qualified professionals. Component ratings and specifications may vary by manufacturer.

Frequently Asked Questions

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