kW to VA Calculator

IEEE 1459IEC 60038
Calculator Input
Enter real power and power factor to calculate apparent power
kW

Real power in kilowatts (0.01 - 100,000 kW)

Power factor (0.1 - 1.0, typical: 0.8-0.95)

Frequently Asked Questions

Common questions about this calculator

VA = kW × 1000 / Power Factor. Example: 5 kW at PF=0.8: VA = 5000 / 0.8 = 6250 VA (6.25 kVA). For resistive loads (PF=1), 1 kW = 1000 VA. For inductive loads like motors, VA is always higher than watts due to reactive power.

VA measures apparent power (total current × voltage), while watts measure real power (useful work). The difference is reactive power in AC circuits. Equipment like UPS, generators, and transformers are rated in VA because they must handle total current flow regardless of how much does useful work.

Convert kW to VA: VA = kW × 1000 / PF. For 2 kW of computer equipment at PF=0.65: VA = 2000/0.65 = 3077 VA. Add 20-25% margin: need 3850 VA minimum. Select UPS with sufficient VA AND watt rating—both matter. Modern UPS specs list both values.

Depends on load type. Resistive (heaters): PF=1.0. Motors at full load: PF=0.85-0.90. Computer PSUs: PF=0.60-0.70 (older) or 0.95+ (Active PFC). LED drivers: PF=0.90-0.95. Mixed loads: PF=0.80-0.85. When unknown, use 0.8 for conservative sizing.

Higher PF reduces VA for same kW load. At PF=0.7, 10 kW needs 14,286 VA. At PF=0.95, same 10 kW needs only 10,526 VA—26% less. This means smaller UPS, cables, and transformers. Power factor correction reduces equipment costs and utility demand charges.

Generators have both kVA and kW ratings. Maximum kW = kVA × rated PF. A 100 kVA generator at 0.8 PF delivers 80 kW maximum. Your load kW ÷ generator PF = required kVA. Always check both ratings: your kW must be under generator kW limit, AND your kVA under generator kVA limit.

Learn More

Example 1: Window AC Unit - Transformer Sizing

Title: Window AC Unit - Transformer Sizing Description: Convert air conditioner real power to apparent power for service upgrade Scenario: 3.5 kW window AC with 0.

  1. Power: 3.

  2. Power Factor: 0.

Result: Apparent Power: 4,118 VA or 4.12 kVA (3.5 kW / 0.85 = 4.12 kVA). Transformer adequacy: Yes, 5 kVA transformer sufficient (82% loaded, within 80-90% optimal range). Starting surge: 15-20 kVA momentary (3-5× running, hard-start kit reduces to 2×). Current draw: 17.2A at 240V (4,118 VA / 240V). Circuit: 20A breaker, 12 AWG wire minimum per NEC 440.

Notes: Formula: VA = kW / PF × 1000. Power factor for HVAC: Compressors 0.75-0.85, fan only 0.95-1.0, combined 0.80-0.90. Transformer loading: Optimal 70-85% for efficiency and headroom. Starting current: Locked rotor amps (LRA) 6× running, time delay relay or soft-start reduces. Efficiency: EER 10-12 typical (12,000 BTU ÷ 3,500W = 3.4 EER, low), modern inverter units EER 14-16. Annual cost: 1,200 hours/summer × 3.5 kW × 0.12 USD/kWh = 504 USD/year.

Example 2: Office Transformer - Load Analysis

Title: Office Transformer - Load Analysis Description: Convert office building load to apparent power for transformer selection Scenario: 75 kW office load (lighting, computers, HVAC) with 0.92 power factor. Need to calculate apparent power for transformer sizing Difficulty: intermediate Industry: Commercial Electrical

Steps:

  1. Real Power (kW): 75 kW

    • Office building load
  2. Power Factor: 0.92

    • Combined load power factor

Result: Apparent Power: 81,522 VA or 81.5 kVA (75 kW / 0.92 = 81.5 kVA). Transformer: 112.5 kVA standard size (next size up from 81.5). Loading: 72% (good for N-1 redundancy). Three-phase: 480V primary, 208Y/120V secondary. Current: 226A secondary (81,500 / (3\sqrt{3} × 208)). Losses: 1.5-2.5 kW no-load, 1.5-2.0 kW at 75% load.

Notes: Standard transformer sizes: 45, 75, 112.5, 150, 225, 300 kVA. Sizing: Select next standard size above calculated kVA with 20-30% margin for growth. Efficiency: Peak at 50-70% load, DOE 2016 standards require 98.0-98.8% at 50% load. Temperature rise: 150°C insulation class common, 80°C rise at full load. Lifespan: 30-40 years, insulation degrades exponentially with temperature. Loading: Per IEEE C57.96, continuous overload 1.2× for well-ventilated indoor transformers. Paralleling: Two 75 kVA for redundancy better than one 150 kVA (N+1 operation during maintenance).

Example 3: Data Center - Transformer Cascading

Title: Data Center - Transformer Cascading Description: Calculate apparent power requirements for multi-tier power distribution Scenario: 2 MW data center with 0.95 power factor. Need to calculate apparent power for transformer cascading and multi-tier power distribution Difficulty: advanced Industry: Data Center

Steps:

  1. Real Power (kW): 2,000 kW (2 MW)

    • Data center load
  2. Power Factor: 0.95

    • Combined load power factor

Result: Apparent Power: 2,105,263 VA or 2.11 MVA (2,000 kW / 0.95 = 2.11 MVA). Transformer configuration (2N): 4× 1.5 MVA (two parallel per side), each loaded 35% during normal operation. Redundancy: Loss of any two transformers maintains full capacity. Utility service: 13.2 kV primary, dual feeds from separate substations (A/B feeds). Annual losses: 60-80 kW transformer losses = 525-700 MWh/year = 52,500 USD-70,000 at 0.10 USD/kWh.

Notes: Data center power hierarchy: Utility (13.2-35 kV) → main transformers (480V) → PDUs → rack (208V). 2N topology: Two independent systems (A + B), each sized for 100% load, highest reliability. Fault tolerance: N, N+1, 2N, 2(N+1) increasing redundancy. Medium voltage: 13.2 kV or 33 kV reduces I²R losses for multi-MW loads. Harmonic mitigation: K-rated transformers (K-13, K-20) for nonlinear loads, or 12-pulse rectification. Selective coordination: Fuse/breaker timing prevents cascade failures. Monitoring: EPMS (electrical power monitoring system) tracks voltage, current, harmonics, PF in real-time. TCO optimization: Amorphous core transformers reduce no-load losses 70%, pay back in 5-7 years for 24/7 operation.