Ohm's Law Calculator

IEC 60364NEC
Calculator Input
Enter 2 of the 3 values to calculate the missing value and power.

ℹ️ Enter any two values (voltage, current, or resistance) to calculate the third value and power using Ohm's Law.

V

Electrical potential difference in volts

A

Electrical current in amperes

Ω

Electrical resistance in ohms

Frequently Asked Questions

Common questions about this calculator

Ohm's Law: V = I × R (Voltage = Current × Resistance). Rearranged: I = V/R and R = V/I. If you know any two values, calculate the third. Example: 12V across 100Ω gives I = 12/100 = 0.12A (120mA). This fundamental law applies to all resistive circuits.

Power formulas derived from P = V × I and Ohm's Law: P = V²/R, P = I²×R, P = V×I. Choose based on known values. For 12V across 10Ω: P = 12²/10 = 14.4W. Or with I=1.2A: P = 12×1.2 = 14.4W. All forms give the same answer.

For purely resistive AC loads, yes—use RMS values. For reactive loads (inductors, capacitors), use impedance Z instead of resistance R: V = I × Z. Impedance includes both resistance and reactance. For simple resistors in AC circuits, Ohm's Law applies directly.

Series: R_total = R1 + R2 + R3... Current is same through all resistors, voltage divides proportionally. For 100Ω and 200Ω in series with 12V: R_total = 300Ω, I = 12/300 = 40mA. V1 = 40mA × 100Ω = 4V, V2 = 40mA × 200Ω = 8V.

Parallel: 1/R_total = 1/R1 + 1/R2... or for two resistors: R_total = (R1×R2)/(R1+R2). Voltage is same across all, current divides. For 100Ω and 200Ω in parallel: R_total = 66.7Ω. At 12V: I_total = 180mA, I1 = 120mA, I2 = 60mA.

V (Volts) = I (Amps) × R (Ohms). Power: P (Watts) = V × I. Common prefixes: mV (millivolts, 10⁻³), mA (milliamps, 10⁻³), kΩ (kilohms, 10³), MΩ (megohms, 10⁶). Keep units consistent—convert all to base units before calculating to avoid errors.

Learn More

Ohm's Law, discovered by Georg Simon Ohm in 1827, defines the fundamental relationship between voltage (V), current (I), and resistance (R) in electrical circuits: V=I×RV = I \times R. This principle forms the foundation for all circuit analysis, design, and troubleshooting in electrical engineering.

Core Relationships: The law states that current through a conductor is directly proportional to voltage and inversely proportional to resistance. With any two values known, the third can be calculated—making circuit behavior predictable and enabling precise component sizing, safety analysis, and power calculations.

Practical Applications: Engineers use Ohm's Law daily for sizing conductors (calculating voltage drop and current capacity), selecting resistors and fuses, troubleshooting circuits by comparing calculated vs. measured values, and determining power dissipation (P = I²R) for thermal management. A 120V circuit with 10Ω resistance draws 12A current and dissipates 1,440W of power.

Important Limitations: Ohm's Law applies only to linear, resistive elements at constant temperature. Non-ohmic devices (diodes, transistors, LEDs) have variable resistance. Temperature changes alter resistance—copper increases ~0.4% per °°C. AC circuits require impedance (Z) instead of pure resistance, accounting for capacitive and inductive reactance.

Circuit Configurations: In series circuits, current is constant and resistances add (Rtotal = R1 + R2 + ...). In parallel circuits, voltage is constant and reciprocal resistances add (1/Rtotal = 1/R1 + 1/R2 + ...). Complex circuits combine both configurations, requiring systematic application of Ohm's Law with Kirchhoff's laws.

Standards Reference: IEC 60038 defines standard voltages. IEEE 141 applies Ohm's Law principles to industrial power systems. NEC Article 310 uses Ohm's Law for conductor ampacity calculations.

Residential Circuit Design

Calculate current draw from voltage and resistance for residential circuit breaker sizing

1
Voltage: 120 V
2
Resistance: 8 Ω
3
Calculate Current: I = V / R = 120V / 8Ω = 15 A

Result

Circuit Current:
15 A
Use 20A circuit breaker (125% of load per NEC 210.20).

Additional Notes

Always add 20% safety margin for real-world installations. Use minimum 14 AWG copper wire for 15A circuits per NEC requirements. Consider voltage drop for long wire runs.

Industrial Motor Installation

Calculate motor current from power, voltage, and power factor for three-phase motor circuit design

1
Motor Power: 10 HP (7.46 kW)
2
Voltage: 480 V
3
Power Factor: 0.85
4
Calculate Current: I = P / ($\sqrt{3}$ × V × PF) = 7460 / (1.732 × 480 × 0.85) ≈ 10.6 A

Result

Motor Full-Load Current:
Approximately **10
6 A**

Additional Notes

Install 20A circuit breaker for motor protection. Include motor overload protection per NEC Article 430. Consider starting current (5-7× running current) for circuit breaker selection.

LED Circuit Design

Calculate current-limiting resistor value for LED circuit using Ohm's Law

1
Supply Voltage: 12 V
2
LED Forward Voltage: 2.0 V
3
Desired LED Current: 20mA (0.020 A)
4
Calculate Resistor Value: R = (Vs - Vf) / I = (12V - 2V) / 0.020A = 500 Ω
5
Calculate Power Dissipation: P = I² × R = (0.020)² × 510 = 0.204 W

Result

Use 510 Ω resistor (standard value) rated for 0.25 W or higher (1/4W resistor).

Additional Notes

Standard resistor value is 510Ω (5% tolerance). Always use higher wattage rating than calculated value for reliability and heat dissipation.

Voltage Drop Analysis

Calculate voltage drop in cable run using Ohm's Law to verify NEC compliance

1
Current: 25 A
2
Cable Length: 200 m (0.2 km)
3
Cable Resistance: 0.387 Ω/km
4
Calculate Total Cable Resistance: R = 0.387 × 0.2 = 0.0774 Ω
5
Calculate Voltage Drop: Vdrop = I × R = 25A × 0.0774Ω = 1.935 V
6
Calculate Percentage Drop: %Drop = (1.935V / 230V) × 100 = 0.84%

Result

Voltage drop of 1.935V (0.84%)

Additional Notes

NEC limits voltage drop to 3% for branch circuits and 5% total. Consider temperature rise in cables under load - resistance increases with temperature. Use larger cable size if voltage drop exceeds limits.